What is the answer to 4^x+4^x+4^x+4^x=4^{17} ?

The answer to 4^x+4^x+4^x+4^x=4^{17} is x=16

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4^x+4^x+4^x+4^x=4^{17}

4^{x} + 4^{x} + 4^{x} + 4^{x} = 4^{17}

x = 16

Solution steps

4^{x} + 4^{x} + 4^{x} + 4^{x} = 4^{17}

Add similar elements:

4^{x} + 4^{x} + 4^{x} + 4^{x} = 4 \cdot 4^{x}

4 \cdot 4^{x} = 4^{17}

Divide both sides by

4

4^{x} = \frac{4 ^{17}}{4}

Simplify

4^{x} = 4^{16}

Apply exponent rules

x = 16

e^{x} - 4 e^{- x} = 0

2^{y} = \frac{1}{4}

e^{x} = 1 + 6 e^{- x}

2^{4} = 2^{x}

2^{n} = 32

What is the answer to 4^x+4^x+4^x+4^x=4^{17} ?
The answer to 4^x+4^x+4^x+4^x=4^{17} is x=16
Solve for x: 4^x+4^x+4^x+4^x=4^{17}
The solution is x=16