What is the answer to 2^{4x}=5 ?

The answer to 2^{4x}=5 is x=(ln(5))/(4ln(2))

Solve for x: 2^{4x}=5

The solution is x=(ln(5))/(4ln(2))

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2^{4 x} = 5

x = \frac{ln ( 5 )}{4 ln ( 2 )}

Decimal Notation

x = 0.58048 \dots

Solution steps

2^{4 x} = 5

Apply exponent rules

4 x ln (2) = ln (5)

Solve

4 x ln (2) = ln (5) : x = \frac{ln ( 5 )}{4 ln ( 2 )}

x = \frac{ln ( 5 )}{4 ln ( 2 )}

200 = 4 (5)^{x}

2^{(- x)} - 2 = 4^{x} - 1

3 6^{12 - m} = 6^{2 m}

3^{x} 4^{x + 2} = 8

3^{2 x - 5} = 81