What is the answer to 6^x+(36)/(6^x)=37 ?

The answer to 6^x+(36)/(6^x)=37 is x=2,x=0

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6^x+(36)/(6^x)=37

6^{x} + \frac{36}{6 ^{x}} = 37

x = 2, x = 0

Solution steps

6^{x} + \frac{36}{6 ^{x}} = 37

Apply exponent rules

6^{x} + 36 (6^{x})^{- 1} = 37

Rewrite the equation with

6^{x} = u

u + 36 (u)^{- 1} = 37

Solve

u + 36 u^{- 1} = 37 : u = 36, u = 1

u = 36, u = 1

Substitute back

u = 6^{x},

solve for

x

Solve

6^{x} = 36 : x = 2

Solve

6^{x} = 1 : x = 0

x = 2, x = 0

Verify Solutions:

x = 2

True

, x = 0

True

The solutions are

x = 2, x = 0

x, 9^{x + 1} + 1 = 10 (3^{x})

2^{x} = \frac{4}{3}

4 \cdot 3^{x} = 7 \cdot 5^{x}

125 = 5^{x}

(1 5^{4 x + 3}) (9^{3 x - 5}) = 5

What is the answer to 6^x+(36)/(6^x)=37 ?
The answer to 6^x+(36)/(6^x)=37 is x=2,x=0
Solve for x: 6^x+(36)/(6^x)=37
The solution is x=2,x=0