What is the answer to (1+0.01)^x=2 ?

The answer to (1+0.01)^x=2 is x=(ln(2))/(ln(1.01))

Solve for x: (1+0.01)^x=2

The solution is x=(ln(2))/(ln(1.01))

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(1 + 0.01)^{x} = 2

x = \frac{ln ( 2 )}{ln ( 1.01 )}

Decimal Notation

x = 69.66071 \dots

Solution steps

(1 + 0.01)^{x} = 2

Apply exponent rules

x ln (1 + 0.01) = ln (2)

Solve

x ln (1 + 0.01) = ln (2) : x = \frac{ln ( 2 )}{ln ( 1.01 )}

x = \frac{ln ( 2 )}{ln ( 1.01 )}

1200 = 500 e^{k}

6 4^{2 x - 5} = 2^{3 - 7 x}

3^{2 x} = 9^{- 2 x - 18}

9^{x - 4} = 7^{- 3 x}

3^{x} + 3^{x + 2} = \frac{10}{3}

What is the answer to (1+0.01)^x=2 ?
The answer to (1+0.01)^x=2 is x=(ln(2))/(ln(1.01))
Solve for x: (1+0.01)^x=2
The solution is x=(ln(2))/(ln(1.01))