What is the answer to 25^{x-3}=125^{4-x} ?

The answer to 25^{x-3}=125^{4-x} is x= 18/5

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25^{x-3}=125^{4-x}

2 5^{x - 3} = 12 5^{4 - x}

x = \frac{18}{5}

Decimal Notation

x = 3.6

Solution steps

2 5^{x - 3} = 12 5^{4 - x}

Apply exponent rules

2 (x - 3) = 3 (4 - x)

Solve

2 (x - 3) = 3 (4 - x) : x = \frac{18}{5}

x = \frac{18}{5}

6^{x} = 9

0.75 \cdot 1 0^{\frac{w}{3}} = 30

x^{x} = 9

\frac{17}{20} = A^{0} e^{k (600)}

x, y = e^{- x^{2}}

What is the answer to 25^{x-3}=125^{4-x} ?
The answer to 25^{x-3}=125^{4-x} is x= 18/5
Solve for x: 25^{x-3}=125^{4-x}
The solution is x= 18/5