What is the answer to 2^{-x}(2^{-x}+2)=15 ?

The answer to 2^{-x}(2^{-x}+2)=15 is x=-(ln(3))/(ln(2))

Solve for x: 2^{-x}(2^{-x}+2)=15

The solution is x=-(ln(3))/(ln(2))

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2^{- x} (2^{- x} + 2) = 15

x = - \frac{ln ( 3 )}{ln ( 2 )}

Decimal Notation

x = - 1.58496 \dots

Solution steps

2^{- x} (2^{- x} + 2) = 15

Rewrite the equation with

2^{- x} = u

u (u + 2) = 15

Solve

u (u + 2) = 15 : u = 3, u = - 5

u = 3, u = - 5

Substitute back

u = 2^{- x},

solve for

x

Solve

2^{- x} = 3 : x = - \frac{ln ( 3 )}{ln ( 2 )}

Solve

2^{- x} = - 5 :

No Solution for

x \in R

x = - \frac{ln ( 3 )}{ln ( 2 )}

t, e^{k t} = \frac{1}{6}

t, e^{k t} = \frac{1}{5}

x, t (x) = - 2^{x - 1}

2 e^{x} = 3 e^{- x} 5

9^{x} - 1 = 2

What is the answer to 2^{-x}(2^{-x}+2)=15 ?
The answer to 2^{-x}(2^{-x}+2)=15 is x=-(ln(3))/(ln(2))
Solve for x: 2^{-x}(2^{-x}+2)=15
The solution is x=-(ln(3))/(ln(2))