What is factor x^4+x^3-8x^2+2x+4 ?

The solution to factor x^4+x^3-8x^2+2x+4 is (x-1)(x-2)(x^2+4x+2)

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factor x^4+x^3-8x^2+2x+4

factor

x^{4} + x^{3} - 8 x^{2} + 2 x + 4

(x - 1) (x - 2) (x^{2} + 4 x + 2)

Solution steps

x^{4} + x^{3} - 8 x^{2} + 2 x + 4

Use the rational root theorem

= (x - 1) \frac{x ^{4} + x ^{3} - 8 x ^{2} + 2 x + 4}{x - 1}

\frac{x ^{4} + x ^{3} - 8 x ^{2} + 2 x + 4}{x - 1} = x^{3} + 2 x^{2} - 6 x - 4

= (x - 1) (x^{3} + 2 x^{2} - 6 x - 4)

Factor

x^{3} + 2 x^{2} - 6 x - 4 : (x - 2) (x^{2} + 4 x + 2)

= (x - 1) (x - 2) (x^{2} + 4 x + 2)

- 2 x^{2} + 4 x + 30

\frac{2 x + 1}{3 x - 2} \geq 0

(x - 1)^{2} \geq 0

6 (\frac{11 - 4 y}{2}) - 5 = 10 - 6 y

(x yz - x y \cdot 0.5) + (w y a - w y \cdot 0.5)

What is factor x^4+x^3-8x^2+2x+4 ?
The solution to factor x^4+x^3-8x^2+2x+4 is (x-1)(x-2)(x^2+4x+2)