What is the answer to 7776^{2x+1}=216^{3x-2} ?

The answer to 7776^{2x+1}=216^{3x-2} is x=-11

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7776^{2x+1}=216^{3x-2}

777 6^{2 x + 1} = 21 6^{3 x - 2}

x = - 11

Solution steps

777 6^{2 x + 1} = 21 6^{3 x - 2}

Apply exponent rules

5 (2 x + 1) = 3 (3 x - 2)

Solve

5 (2 x + 1) = 3 (3 x - 2) : x = - 11

x = - 11

5^{x^{2} - 3 x} = \frac{1}{25}

7^{\frac{x}{4}} = 343

14 e^{3 x + 2} = 560

3^{z} = 8 1^{2}

e^{x} + e^{- x} = 6

What is the answer to 7776^{2x+1}=216^{3x-2} ?
The answer to 7776^{2x+1}=216^{3x-2} is x=-11
Solve for x: 7776^{2x+1}=216^{3x-2}
The solution is x=-11