What is the answer to 4*3^{4x+1}=2 ?

The answer to 4*3^{4x+1}=2 is x=-(ln(6))/(4ln(3))

Solve for x: 4*3^{4x+1}=2

The solution is x=-(ln(6))/(4ln(3))

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4 \cdot 3^{4 x + 1} = 2

x = - \frac{ln ( 6 )}{4 ln ( 3 )}

Decimal Notation

x = - 0.40773 \dots

Solution steps

4 \cdot 3^{4 x + 1} = 2

Divide both sides by

4

3^{4 x + 1} = \frac{1}{2}

Apply exponent rules

(4 x + 1) ln (3) = ln (\frac{1}{2})

Solve

(4 x + 1) ln (3) = ln (\frac{1}{2}) : x = - \frac{ln ( 6 )}{4 ln ( 3 )}

x = - \frac{ln ( 6 )}{4 ln ( 3 )}

e^{2 x} - 8 e^{x} + 12 = 0

2^{x} = 4 x

\frac{1}{2} = 2^{x}

8 (e)^{2 x + 1} = 4

0 = 2^{x} - 1

What is the answer to 4*3^{4x+1}=2 ?
The answer to 4*3^{4x+1}=2 is x=-(ln(6))/(4ln(3))
Solve for x: 4*3^{4x+1}=2
The solution is x=-(ln(6))/(4ln(3))