What is the answer to 5^{x+2}=7^{x-2} ?

The answer to 5^{x+2}=7^{x-2} is x=(2ln(35))/(ln(7)-ln(5))

Solve for x: 5^{x+2}=7^{x-2}

The solution is x=(2ln(35))/(ln(7)-ln(5))

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5^{x + 2} = 7^{x - 2}

x = \frac{2 ln ( 35 )}{ln ( 7 ) - ln ( 5 )}

Decimal Notation

x = 21.13308 \dots

Solution steps

5^{x + 2} = 7^{x - 2}

Apply exponent rules

(x + 2) ln (5) = (x - 2) ln (7)

Solve

(x + 2) ln (5) = (x - 2) ln (7) : x = \frac{2 ln ( 35 )}{ln ( 7 ) - ln ( 5 )}

x = \frac{2 ln ( 35 )}{ln ( 7 ) - ln ( 5 )}

e^{- 0.05 x} = 0.01

9^{x} = \frac{1}{81}

5^{3 x + 7} = 2 5^{x - 4}

9^{x} - 10 \cdot 3^{x} + 9 = 0

3 x - e^{x} = 0

What is the answer to 5^{x+2}=7^{x-2} ?
The answer to 5^{x+2}=7^{x-2} is x=(2ln(35))/(ln(7)-ln(5))
Solve for x: 5^{x+2}=7^{x-2}
The solution is x=(2ln(35))/(ln(7)-ln(5))