What is the answer to 3^x=2^{x+3} ?

The answer to 3^x=2^{x+3} is x=(3ln(2))/(ln(3)-ln(2))

Solve for x: 3^x=2^{x+3}

The solution is x=(3ln(2))/(ln(3)-ln(2))

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3^{x} = 2^{x + 3}

x = \frac{3 ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

Decimal Notation

x = 5.12853 \dots

Solution steps

3^{x} = 2^{x + 3}

Apply exponent rules

x ln (3) = (x + 3) ln (2)

Solve

x ln (3) = (x + 3) ln (2) : x = \frac{3 ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

x = \frac{3 ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

0.5 = 320 e^{- 3.1 t}

5^{2 x + 1} - 6 (5 x) + 1 = 0

9^{x} = 729

7^{x + 3} = e^{x}

3 2^{x} = 8^{150}

What is the answer to 3^x=2^{x+3} ?
The answer to 3^x=2^{x+3} is x=(3ln(2))/(ln(3)-ln(2))
Solve for x: 3^x=2^{x+3}
The solution is x=(3ln(2))/(ln(3)-ln(2))