What is the answer to solvefor x,2^x-2^y=2016 ?

The answer to solvefor x,2^x-2^y=2016 is x=(ln(2016+2^y))/(ln(2))

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solvefor x,2^x-2^y=2016

solve for

x, 2^{x} - 2^{y} = 2016

x = \frac{ln ( 2016 + 2 ^{y} )}{ln ( 2 )}

Solution steps

2^{x} - 2^{y} = 2016

Move

2^{y}

to the right side

2^{x} = 2016 + 2^{y}

Apply exponent rules

x ln (2) = ln (2016 + 2^{y})

Solve

x ln (2) = ln (2016 + 2^{y}) : x = \frac{ln ( 2016 + 2 ^{y} )}{ln ( 2 )}

x = \frac{ln ( 2016 + 2 ^{y} )}{ln ( 2 )}

4^{x + 2} = 7^{x - 1}

5^{x + 7} = 3

n = 4^{x}

2^{x} e^{3 x + 1} = 10

3 2^{2 x - 1} = \frac{1}{8}

What is the answer to solvefor x,2^x-2^y=2016 ?
The answer to solvefor x,2^x-2^y=2016 is x=(ln(2016+2^y))/(ln(2))