What is the answer to 3^x=\sqrt[5]{27} ?

The answer to 3^x=\sqrt[5]{27} is x= 3/5

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3^x=\sqrt[5]{27}

x = \frac{3}{5}

Decimal Notation

x = 0.6

Solution steps

Apply exponent rules

x = \frac{3}{5}

2^{5 x + 15} = 4^{10 x + 5}

e^{0.05 x} = 3

5 0^{x} = 2

e^{3 x + 6} = 8

3^{2 x} + 2 \cdot 3^{x} - 15 = 0

What is the answer to 3^x=\sqrt[5]{27} ?
The answer to 3^x=\sqrt[5]{27} is x= 3/5
Solve for x: 3^x=\sqrt[5]{27}
The solution is x= 3/5