What is the answer to 4^{x+2}=51 ?

The answer to 4^{x+2}=51 is x=(ln(51))/(2ln(2))-2

Solve for x: 4^{x+2}=51

The solution is x=(ln(51))/(2ln(2))-2

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4^{x + 2} = 51

x = \frac{ln ( 51 )}{2 ln ( 2 )} - 2

Decimal Notation

x = 0.83621 \dots

Solution steps

4^{x + 2} = 51

Apply exponent rules

(x + 2) ln (4) = ln (51)

Solve

(x + 2) ln (4) = ln (51) : x = \frac{ln ( 51 )}{2 ln ( 2 )} - 2

x = \frac{ln ( 51 )}{2 ln ( 2 )} - 2

\frac{- 32}{( - 2 ) ^{n}} = 4

3^{x} + 9^{x} = 90

1 2^{x - 2} = 4^{x}

9^{- x + 1} = 3^{x + 11}

e^{a x} = c e^{b x}

What is the answer to 4^{x+2}=51 ?
The answer to 4^{x+2}=51 is x=(ln(51))/(2ln(2))-2
Solve for x: 4^{x+2}=51
The solution is x=(ln(51))/(2ln(2))-2