What is the answer to (\sqrt[3]{2})^{x+10}=8 ?

The answer to (\sqrt[3]{2})^{x+10}=8 is x=-1

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(\sqrt[3]{2})^{x+10}=8

x = - 1

Solution steps

Apply exponent rules

\frac{1}{3} (x + 10) = 3

Solve

\frac{1}{3} (x + 10) = 3 : x = - 1

x = - 1

\frac{1}{2} = e^{x}

4 e^{x} = 1

9 e^{5 x} = 1269

2 7^{x + 2} = 9^{2 x}

y, x^{y} = 0

What is the answer to (\sqrt[3]{2})^{x+10}=8 ?
The answer to (\sqrt[3]{2})^{x+10}=8 is x=-1
Solve for x: (\sqrt[3]{2})^{x+10}=8
The solution is x=-1