What are the solutions to the equation 15x^2+13x=0 ?

The solutions to the equation 15x^2+13x=0 are x=0,x=-13/15

Find the zeros of 15x^2+13x=0

The zeros of 15x^2+13x=0 are x=0,x=-13/15

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15 x^{2} + 13 x = 0

x = 0, x = - \frac{13}{15}

Solution steps

15 x^{2} + 13 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 15 \cdot 0}{2 \cdot 15}

1 3^{2} - 4 \cdot 15 \cdot 0 = 13

x_{1, 2} = \frac{- 13 \pm 13}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 13 + 13}{2 \cdot 15}, x_{2} = \frac{- 13 - 13}{2 \cdot 15}

x = \frac{- 13 + 13}{2 \cdot 15} : 0

x = \frac{- 13 - 13}{2 \cdot 15} : - \frac{13}{15}

The solutions to the quadratic equation are:

x = 0, x = - \frac{13}{15}

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What are the solutions to the equation 15x^2+13x=0 ?
The solutions to the equation 15x^2+13x=0 are x=0,x=-13/15
Find the zeros of 15x^2+13x=0
The zeros of 15x^2+13x=0 are x=0,x=-13/15