What is the answer to 2*2^x=(2^{3x})/(32) ?

The answer to 2*2^x=(2^{3x})/(32) is x=3

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2*2^x=(2^{3x})/(32)

2 \cdot 2^{x} = \frac{2 ^{3 x}}{32}

x = 3

Solution steps

2 \cdot 2^{x} = \frac{2 ^{3 x}}{32}

Multiply both sides by

32

2 \cdot 2^{x} \cdot 32 = \frac{2 ^{3 x}}{32} \cdot 32

Simplify

64 \cdot 2^{x} = 2^{3 x}

Apply exponent rules

x + 6 = 3 x

Solve

x + 6 = 3 x : x = 3

x = 3

e^{x} + 12 e^{- x} = 7

1 0^{2 x^{2} - 10 x + 1} = e

2^{5^{x - 3}} = 2^{2 5^{x}}

e^{2 x} - 4 \cdot e^{x} + 4 = 0

4^{x^{2}} - 2^{x^{2}} = 240

What is the answer to 2*2^x=(2^{3x})/(32) ?
The answer to 2*2^x=(2^{3x})/(32) is x=3
Solve for x: 2*2^x=(2^{3x})/(32)
The solution is x=3