What is the answer to 9^x+3=28(3^{x-1}) ?

The answer to 9^x+3=28(3^{x-1}) is x=2,x=-1

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9^x+3=28(3^{x-1})

9^{x} + 3 = 28 (3^{x - 1})

x = 2, x = - 1

Solution steps

9^{x} + 3 = 28 (3^{x - 1})

Apply exponent rules

(3^{x})^{2} + 3 = 28 \cdot 3^{x} \cdot 3^{- 1}

Rewrite the equation with

3^{x} = u

(u)^{2} + 3 = 28 u \cdot 3^{- 1}

Solve

u^{2} + 3 = 28 u \cdot 3^{- 1} : u = 9, u = \frac{1}{3}

u = 9, u = \frac{1}{3}

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 9 : x = 2

Solve

3^{x} = \frac{1}{3} : x = - 1

x = 2, x = - 1

4^{x - 10} = (\frac{1}{64})^{5 x + 2}

4096 = 4^{n - 1}

e^{- 0.3 t} = 8

2^{x} = 3 e^{4 x}

1000 = 1 0^{x}

What is the answer to 9^x+3=28(3^{x-1}) ?
The answer to 9^x+3=28(3^{x-1}) is x=2,x=-1
Solve for x: 9^x+3=28(3^{x-1})
The solution is x=2,x=-1