What is the answer to 0=-3^{2x}+2 ?

The answer to 0=-3^{2x}+2 is x=(ln(2))/(2ln(3))

Solve for x: 0=-3^{2x}+2

The solution is x=(ln(2))/(2ln(3))

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0 = - 3^{2 x} + 2

x = \frac{ln ( 2 )}{2 ln ( 3 )}

Decimal Notation

x = 0.31546 \dots

Solution steps

0 = - 3^{2 x} + 2

Add

3^{2 x}

to both sides

0 + 3^{2 x} = - 3^{2 x} + 2 + 3^{2 x}

Simplify

3^{2 x} = 2

Apply exponent rules

2 x ln (3) = ln (2)

Solve

2 x ln (3) = ln (2) : x = \frac{ln ( 2 )}{2 ln ( 3 )}

x = \frac{ln ( 2 )}{2 ln ( 3 )}

2 5^{x} + 1 = 26 (5^{x - 1})

5^{x} - 5^{(5 - x)} = 150

4^{x} = 89

2^{x + 3} - 2^{x} = k (x) (2^{x})

2^{5 x - 1} = 3^{2 x}

What is the answer to 0=-3^{2x}+2 ?
The answer to 0=-3^{2x}+2 is x=(ln(2))/(2ln(3))
Solve for x: 0=-3^{2x}+2
The solution is x=(ln(2))/(2ln(3))