What is the answer to 9(3^x)=27^{x-1} ?

The answer to 9(3^x)=27^{x-1} is x= 5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9(3^x)=27^{x-1}

9 (3^{x}) = 2 7^{x - 1}

x = \frac{5}{2}

Decimal Notation

x = 2.5

Solution steps

9 (3^{x}) = 2 7^{x - 1}

Apply exponent rules

x + 2 = 3 (x - 1)

Solve

x + 2 = 3 (x - 1) : x = \frac{5}{2}

x = \frac{5}{2}

7^{x} = 6

8^{- x + 3} = 4^{x + 2}

e^{2 t + 1} - 9 e^{1 - t} = 0

3^{2 a} = 3^{- a}