What is the answer to solvefor x,2e^{-2x}=5 ?

The answer to solvefor x,2e^{-2x}=5 is x=-(ln(5/2))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,2e^{-2x}=5

solve for

x, 2 e^{- 2 x} = 5

x = - \frac{ln ( \frac{5}{2} )}{2}

Decimal Notation

x = - 0.45814 \dots

Solution steps

2 e^{- 2 x} = 5

Divide both sides by

2

e^{- 2 x} = \frac{5}{2}

Apply exponent rules

- 2 x = ln (\frac{5}{2})

Solve

- 2 x = ln (\frac{5}{2}) : x = - \frac{ln ( \frac{5}{2} )}{2}

x = - \frac{ln ( \frac{5}{2} )}{2}

e^{x} - 4 x = 0

x^{8} = e^{x}

x, e^{x} = 5

\frac{1}{8} = 2^{n}

9^{x} = 3^{1 - 2 x}

What is the answer to solvefor x,2e^{-2x}=5 ?
The answer to solvefor x,2e^{-2x}=5 is x=-(ln(5/2))/2