What is the answer to 64^{x-1}=4^{x+2} ?

The answer to 64^{x-1}=4^{x+2} is x= 5/2

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64^{x-1}=4^{x+2}

6 4^{x - 1} = 4^{x + 2}

x = \frac{5}{2}

Decimal Notation

x = 2.5

Solution steps

6 4^{x - 1} = 4^{x + 2}

Apply exponent rules

3 (x - 1) = x + 2

Solve

3 (x - 1) = x + 2 : x = \frac{5}{2}

x = \frac{5}{2}

x, e^{y} = e^{x} + c

3^{x + 1} = 243

5^{5 x - 1} = 3^{1 - 2 x}

n, (x y)^{n} = x^{n} y^{n}

e^{x - 2} + 10 = 3

What is the answer to 64^{x-1}=4^{x+2} ?
The answer to 64^{x-1}=4^{x+2} is x= 5/2
Solve for x: 64^{x-1}=4^{x+2}
The solution is x= 5/2