What is the answer to 8^x=9^{x-1} ?

The answer to 8^x=9^{x-1} is x=(2ln(3))/(2ln(3)-3ln(2))

Solve for x: 8^x=9^{x-1}

The solution is x=(2ln(3))/(2ln(3)-3ln(2))

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8^{x} = 9^{x - 1}

x = \frac{2 ln ( 3 )}{2 ln ( 3 ) - 3 ln ( 2 )}

Decimal Notation

x = 18.65484 \dots

Solution steps

8^{x} = 9^{x - 1}

Apply exponent rules

x ln (8) = (x - 1) ln (9)

Solve

x ln (8) = (x - 1) ln (9) : x = \frac{2 ln ( 3 )}{2 ln ( 3 ) - 3 ln ( 2 )}

x = \frac{2 ln ( 3 )}{2 ln ( 3 ) - 3 ln ( 2 )}

3 2^{n} = 2

e^{7 - 4 x} = 2

e^{7 - 4 x} = 9

3^{x} = 24 3^{4}

8.5 = 15 (1 - e^{- k (20)})

What is the answer to 8^x=9^{x-1} ?
The answer to 8^x=9^{x-1} is x=(2ln(3))/(2ln(3)-3ln(2))
Solve for x: 8^x=9^{x-1}
The solution is x=(2ln(3))/(2ln(3)-3ln(2))