What is the answer to (1/27)^{4-x}=9^{2x-1} ?

The answer to (1/27)^{4-x}=9^{2x-1} is x=-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1/27)^{4-x}=9^{2x-1}

(\frac{1}{27})^{4 - x} = 9^{2 x - 1}

x = - 10

Solution steps

(\frac{1}{27})^{4 - x} = 9^{2 x - 1}

Apply exponent rules

- 3 (4 - x) = 2 (2 x - 1)

Solve

- 3 (4 - x) = 2 (2 x - 1) : x = - 10

x = - 10

5 m e^{m x} = 2 e^{m x}

2^{n} = 0

(510)^{n} = 3493.88

\frac{3 ^{x} - 3 ^{- x}}{2} = 5

786000 = 247000 e^{r \cdot 17}

What is the answer to (1/27)^{4-x}=9^{2x-1} ?
The answer to (1/27)^{4-x}=9^{2x-1} is x=-10
Solve for x: (1/27)^{4-x}=9^{2x-1}
The solution is x=-10