What is the answer to 2^{8x+5}=8^{x^2-2} ?

The answer to 2^{8x+5}=8^{x^2-2} is x= 11/3 ,x=-1

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2^{8x+5}=8^{x^2-2}

2^{8 x + 5} = 8^{x^{2} - 2}

x = \frac{11}{3}, x = - 1

Decimal Notation

x = 3.66666 \dots, x = - 1

Solution steps

2^{8 x + 5} = 8^{x^{2} - 2}

Apply exponent rules

8 x + 5 = 3 (x^{2} - 2)

Solve

8 x + 5 = 3 (x^{2} - 2) : x = \frac{11}{3}, x = - 1

x = \frac{11}{3}, x = - 1

e^{x} e^{x + 1} = 10

4 9^{x} - 7^{x + 1} = 8

4 9^{5 x + 2} = (\frac{1}{7})^{11 - x}

e^{x^{2}} = 1

a, e^{a x} = 1 + x^{2}

What is the answer to 2^{8x+5}=8^{x^2-2} ?
The answer to 2^{8x+5}=8^{x^2-2} is x= 11/3 ,x=-1
Solve for x: 2^{8x+5}=8^{x^2-2}
The solution is x= 11/3 ,x=-1