What is the answer to 5^{2x-4}=2^{5x} ?

The answer to 5^{2x-4}=2^{5x} is x=(4ln(5))/(2ln(5)-5ln(2))

Solve for x: 5^{2x-4}=2^{5x}

The solution is x=(4ln(5))/(2ln(5)-5ln(2))

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5^{2 x - 4} = 2^{5 x}

x = \frac{4 ln ( 5 )}{2 ln ( 5 ) - 5 ln ( 2 )}

Decimal Notation

x = - 26.07854 \dots

Solution steps

5^{2 x - 4} = 2^{5 x}

Apply exponent rules

(2 x - 4) ln (5) = 5 x ln (2)

Solve

(2 x - 4) ln (5) = 5 x ln (2) : x = \frac{4 ln ( 5 )}{2 ln ( 5 ) - 5 ln ( 2 )}

x = \frac{4 ln ( 5 )}{2 ln ( 5 ) - 5 ln ( 2 )}

5 e^{x + 2} = 7

2^{x - 1} + 2^{x - 2} + 2^{x - 3} = 112

e^{e^{x}} = 1

e^{e^{x}} = 5

3^{5^{x}} = 5^{3^{x}}

What is the answer to 5^{2x-4}=2^{5x} ?
The answer to 5^{2x-4}=2^{5x} is x=(4ln(5))/(2ln(5)-5ln(2))
Solve for x: 5^{2x-4}=2^{5x}
The solution is x=(4ln(5))/(2ln(5)-5ln(2))