What is the answer to e^z+1=0 ?

The answer to e^z+1=0 is No Solution for z\in\mathbb{R}

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e^z+1=0

e^{z} + 1 = 0

No Solution for z \in R

Solution steps

e^{z} + 1 = 0

Subtract

1

from both sides

e^{z} + 1 - 1 = 0 - 1

Simplify

e^{z} = - 1

a^{f (z)}

cannot be zero or negative for

z \in R

No Solution for z \in R

8 x^{3} e^{- 2 x} - 4 x^{4} e^{- 2 x} = 0

9^{x - 2} = 27

3^{1 - x} = 243

x, e^{x y} x = 0

15.48 = 16 + 54 e^{- k (30)}

What is the answer to e^z+1=0 ?
The answer to e^z+1=0 is No Solution for z\in\mathbb{R}