What is the answer to 4^{-x+1}=2^{2x} ?

The answer to 4^{-x+1}=2^{2x} is x= 1/2

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4^{-x+1}=2^{2x}

4^{- x + 1} = 2^{2 x}

x = \frac{1}{2}

Solution steps

4^{- x + 1} = 2^{2 x}

Apply exponent rules

2 (- x + 1) = 2 x

Solve

2 (- x + 1) = 2 x : x = \frac{1}{2}

x = \frac{1}{2}

9^{x} = 3^{x + 2}

z, 45 = e^{2 x + 2 y + z}

8 + 3 e^{4 - 9 z} = 1

2^{x} + 4 \cdot 2^{- x} = 5

e^{2} x - 5 e^{x} + 6 = 0