What is the answer to 243^{x+2}*9^{2x-1}=9 ?

The answer to 243^{x+2}*9^{2x-1}=9 is x=-2/3

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243^{x+2}*9^{2x-1}=9

24 3^{x + 2} \cdot 9^{2 x - 1} = 9

x = - \frac{2}{3}

Decimal Notation

x = - 0.66666 \dots

Solution steps

24 3^{x + 2} \cdot 9^{2 x - 1} = 9

Apply exponent rules

5 (x + 2) + 2 (2 x - 1) = 2

Solve

5 (x + 2) + 2 (2 x - 1) = 2 : x = - \frac{2}{3}

x = - \frac{2}{3}

200 = 100 (1 + \frac{8}{100})^{x}

8^{x - 3} = 6 4^{3 - x}

\frac{5 ^{x + 1} - 20}{10 + 5 ^{x}} = 3

10 + 2 \cdot 2^{x} = 18

5^{x} = - x + 6

What is the answer to 243^{x+2}*9^{2x-1}=9 ?
The answer to 243^{x+2}*9^{2x-1}=9 is x=-2/3
Solve for x: 243^{x+2}*9^{2x-1}=9
The solution is x=-2/3