What is the answer to solvefor x,2^x+3^y=41 ?

The answer to solvefor x,2^x+3^y=41 is x=(ln(41-3^y))/(ln(2))

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solvefor x,2^x+3^y=41

solve for

x, 2^{x} + 3^{y} = 41

x = \frac{ln ( 41 - 3 ^{y} )}{ln ( 2 )}

Solution steps

2^{x} + 3^{y} = 41

Move

3^{y}

to the right side

2^{x} = 41 - 3^{y}

Apply exponent rules

x ln (2) = ln (41 - 3^{y})

Solve

x ln (2) = ln (41 - 3^{y}) : x = \frac{ln ( 41 - 3 ^{y} )}{ln ( 2 )}

x = \frac{ln ( 41 - 3 ^{y} )}{ln ( 2 )}

3^{x} + 2 \cdot 3^{x - 1} = 45

ln (e^{- x}) = 3

(1 0^{x})^{1 - x} = 1

5^{\frac{1}{3}} \cdot 5^{x} = 5

9^{x + 2} = 9^{x} + 240

What is the answer to solvefor x,2^x+3^y=41 ?
The answer to solvefor x,2^x+3^y=41 is x=(ln(41-3^y))/(ln(2))