What is the answer to 2^{2x}-34*2^x+64=0 ?

The answer to 2^{2x}-34*2^x+64=0 is x=5,x=1

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2^{2x}-34*2^x+64=0

2^{2 x} - 34 \cdot 2^{x} + 64 = 0

x = 5, x = 1

Solution steps

2^{2 x} - 34 \cdot 2^{x} + 64 = 0

Apply exponent rules

(2^{x})^{2} - 34 \cdot 2^{x} + 64 = 0

Rewrite the equation with

2^{x} = u

(u)^{2} - 34 u + 64 = 0

Solve

u^{2} - 34 u + 64 = 0 : u = 32, u = 2

u = 32, u = 2

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 32 : x = 5

Solve

2^{x} = 2 : x = 1

x = 5, x = 1

3^{2 x + 5} = \frac{1}{27}

2^{x + 2} - 3 \cdot 2^{x - 1} = 20

(e^{x})^{2} - 7 e^{x} + 10 = 0

e^{3 x - 5} = 17

2^{2 x + 3} = 1

What is the answer to 2^{2x}-34*2^x+64=0 ?
The answer to 2^{2x}-34*2^x+64=0 is x=5,x=1
Solve for x: 2^{2x}-34*2^x+64=0
The solution is x=5,x=1