What is the answer to 5*2^{3x}=21 ?

The answer to 5*2^{3x}=21 is x=(ln(21/5))/(3ln(2))

Solve for x: 5*2^{3x}=21

The solution is x=(ln(21/5))/(3ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 \cdot 2^{3 x} = 21

x = \frac{ln ( \frac{21}{5} )}{3 ln ( 2 )}

Solution steps

5 \cdot 2^{3 x} = 21

Divide both sides by

5

2^{3 x} = \frac{21}{5}

Apply exponent rules

3 x ln (2) = ln (\frac{21}{5})

Solve

3 x ln (2) = ln (\frac{21}{5}) : x = \frac{ln ( \frac{21}{5} )}{3 ln ( 2 )}

x = \frac{ln ( \frac{21}{5} )}{3 ln ( 2 )}

e^{x} + e^{- x} = 1

3^{2 x + 1} - 8 (3^{x}) = 3

3^{y} + 3^{y + 2} = 90

8 (\frac{1}{2})^{x} + 2 = 2^{x}

x^{x^{9}} = 3^{3}

What is the answer to 5*2^{3x}=21 ?
The answer to 5*2^{3x}=21 is x=(ln(21/5))/(3ln(2))
Solve for x: 5*2^{3x}=21
The solution is x=(ln(21/5))/(3ln(2))