What is the answer to 2^x=37 ?

The answer to 2^x=37 is x=(ln(37))/(ln(2))

The solution is x=(ln(37))/(ln(2))

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2^x=37

2^{x} = 37

x = \frac{ln ( 37 )}{ln ( 2 )}

Solution steps

2^{x} = 37

Apply exponent rules

x ln (2) = ln (37)

Solve

x ln (2) = ln (37) : x = \frac{ln ( 37 )}{ln ( 2 )}

x = \frac{ln ( 37 )}{ln ( 2 )}

2^{x} = 28

2 5^{x + 1} + 3 \cdot 5^{x + 2} - 16 = 0

2. 5^{- 4 x} = 6.4

15 = 3 (8)^{- x - 4}

3^{2 x} + 3^{x + 1} - 4 = 0