What is the answer to 3^x5^{x+1}=12^{x-1} ?

The answer to 3^x5^{x+1}=12^{x-1} is x=-(ln(60))/(ln(5/4))

Solve for x: 3^x5^{x+1}=12^{x-1}

The solution is x=-(ln(60))/(ln(5/4))

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3^{x} 5^{x + 1} = 1 2^{x - 1}

x = - \frac{ln ( 60 )}{ln ( \frac{5}{4} )}

Solution steps

3^{x} \cdot 5^{x + 1} = 1 2^{x - 1}

Apply exponent rules

x ln (15) + ln (5^{1}) = (x - 1) ln (12)

Solve

x ln (15) + ln (5^{1}) = (x - 1) ln (12) : x = - \frac{ln ( 60 )}{ln ( \frac{5}{4} )}

x = - \frac{ln ( 60 )}{ln ( \frac{5}{4} )}

3^{2 x} = - 81

- 5 e^{- 5 x} = 0

e^{x} - 8 = 0

9^{x} = 10

5^{7 x + 5} = 2

What is the answer to 3^x5^{x+1}=12^{x-1} ?
The answer to 3^x5^{x+1}=12^{x-1} is x=-(ln(60))/(ln(5/4))
Solve for x: 3^x5^{x+1}=12^{x-1}
The solution is x=-(ln(60))/(ln(5/4))