What are the solutions to the equation x^2=-6x+7 ?

The solutions to the equation x^2=-6x+7 are x=1,x=-7

Find the zeros of x^2=-6x+7

The zeros of x^2=-6x+7 are x=1,x=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} = - 6 x + 7

x = 1, x = - 7

Solution steps

x^{2} = - 6 x + 7

Move

7

to the left side

x^{2} - 7 = - 6 x

Move

6 x

to the left side

x^{2} - 7 + 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 7) = 8

x_{1, 2} = \frac{- 6 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 8}{2 \cdot 1}, x_{2} = \frac{- 6 - 8}{2 \cdot 1}

x = \frac{- 6 + 8}{2 \cdot 1} : 1

x = \frac{- 6 - 8}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 1, x = - 7

x^{2} - 8 x = - 16

(p - q) (p - q)

(\infty - 3) \infty < 4 (\infty + 2)

54 g + 71 \leq - 37

- 250

What are the solutions to the equation x^2=-6x+7 ?
The solutions to the equation x^2=-6x+7 are x=1,x=-7
Find the zeros of x^2=-6x+7
The zeros of x^2=-6x+7 are x=1,x=-7