What is the answer to 8^{2x}-1=29 ?

The answer to 8^{2x}-1=29 is x=(ln(30))/(6ln(2))

Solve for x: 8^{2x}-1=29

The solution is x=(ln(30))/(6ln(2))

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8^{2 x} - 1 = 29

x = \frac{ln ( 30 )}{6 ln ( 2 )}

Decimal Notation

x = 0.81781 \dots

Solution steps

8^{2 x} - 1 = 29

Move

1

to the right side

8^{2 x} = 30

Apply exponent rules

2 x ln (8) = ln (30)

Solve

2 x ln (8) = ln (30) : x = \frac{ln ( 30 )}{6 ln ( 2 )}

x = \frac{ln ( 30 )}{6 ln ( 2 )}

z, 1 = e^{2 x + 2 y + z}

1 0^{x} = 100000

4^{x} - 4^{- 2 x} = 3

14 (3 + e^{- x})^{- 1} = 3

100 e^{- 0.1 x} x = 0

What is the answer to 8^{2x}-1=29 ?
The answer to 8^{2x}-1=29 is x=(ln(30))/(6ln(2))
Solve for x: 8^{2x}-1=29
The solution is x=(ln(30))/(6ln(2))