What is the answer to 27^{9^{x-3}}=\sqrt[3]{3} ?

The answer to 27^{9^{x-3}}=\sqrt[3]{3} is x=2

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27^{9^{x-3}}=\sqrt[3]{3}

x = 2

Solution steps

Apply exponent rules

1 + 2 (x - 3) = - 1

Solve

1 + 2 (x - 3) = - 1 : x = 2

x = 2

8^{2 x - 1} = \frac{1}{2} 32

4^{x + 1} - 5 (2^{x}) + 1 = 0

2^{x - 1} = \frac{1}{4}

9^{8 - x} = 2 7^{x - 3}

- 12 e^{- x} + 8 = 7

What is the answer to 27^{9^{x-3}}=\sqrt[3]{3} ?
The answer to 27^{9^{x-3}}=\sqrt[3]{3} is x=2
Solve for x: 27^{9^{x-3}}=\sqrt[3]{3}
The solution is x=2