What is the answer to 2^{(x-2)(2x+1)}=1 ?

The answer to 2^{(x-2)(2x+1)}=1 is x=2,x=-1/2

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2^{(x-2)(2x+1)}=1

2^{(x - 2) (2 x + 1)} = 1

x = 2, x = - \frac{1}{2}

Decimal Notation

x = 2, x = - 0.5

Solution steps

2^{(x - 2) (2 x + 1)} = 1

Apply exponent rules

(x - 2) (2 x + 1) ln (2) = ln (1)

Solve

(x - 2) (2 x + 1) ln (2) = ln (1) : x = 2, x = - \frac{1}{2}

x = 2, x = - \frac{1}{2}

e^{2 x} + 3 x = 4

1 6^{x + 3} = 6 4^{2 x - 5}

2500 = 5000 e^{- 0.8 t}

3 e^{4 t} = 200

y, x = e^{- y^{2}}

What is the answer to 2^{(x-2)(2x+1)}=1 ?
The answer to 2^{(x-2)(2x+1)}=1 is x=2,x=-1/2
Solve for x: 2^{(x-2)(2x+1)}=1
The solution is x=2,x=-1/2