What is factor 2x^5-32y^4x ?

The solution to factor 2x^5-32y^4x is 2x(x^2+4y^2)(x+2y)(x-2y)

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factor 2x^5-32y^4x

factor

2 x^{5} - 32 y^{4} x

2 x (x^{2} + 4 y^{2}) (x + 2 y) (x - 2 y)

Solution steps

2 x^{5} - 32 y^{4} x

Factor out common term

2 x : 2 x (x^{4} - 16 y^{4})

= 2 x (x^{4} - 16 y^{4})

Factor

x^{4} - 16 y^{4} : (x^{2} + 4 y^{2}) (x + 2 y) (x - 2 y)

= 2 x (x^{2} + 4 y^{2}) (x + 2 y) (x - 2 y)

1 - \frac{a}{b}

(x^{- 1})^{2}

∣ 8 x - 4 ∣ = 9 x - 5

(\frac{3}{4})^{- 2}

What is factor 2x^5-32y^4x ?
The solution to factor 2x^5-32y^4x is 2x(x^2+4y^2)(x+2y)(x-2y)