What is the answer to (2.79)^{x-1}=3.377^x ?

The answer to (2.79)^{x-1}=3.377^x is x=(ln(2.79))/(ln(2.79)-ln(3.377))

Solve for x: (2.79)^{x-1}=3.377^x

The solution is x=(ln(2.79))/(ln(2.79)-ln(3.377))

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(2.79)^{x - 1} = 3.37 7^{x}

x = \frac{ln ( 2.79 )}{ln ( 2.79 ) - ln ( 3.377 )}

Decimal Notation

x = - 5.37346 \dots

Solution steps

(2.79)^{x - 1} = 3.37 7^{x}

Apply exponent rules

(x - 1) ln (2.79) = x ln (3.377)

Solve

(x - 1) ln (2.79) = x ln (3.377) : x = \frac{ln ( 2.79 )}{ln ( 2.79 ) - ln ( 3.377 )}

x = \frac{ln ( 2.79 )}{ln ( 2.79 ) - ln ( 3.377 )}

360 e^{- 0.06 t} = 240 e^{0.04 t}

2^{1 6^{x}} = 1 6^{2^{x}}

e^{6 - 4 x} = 8

(\frac{1}{9})^{x + 2} = 3

3^{5 x - 4} = 6

What is the answer to (2.79)^{x-1}=3.377^x ?
The answer to (2.79)^{x-1}=3.377^x is x=(ln(2.79))/(ln(2.79)-ln(3.377))
Solve for x: (2.79)^{x-1}=3.377^x
The solution is x=(ln(2.79))/(ln(2.79)-ln(3.377))