What is the answer to 32^{x-2}=8^{(x+6)/3} ?

The answer to 32^{x-2}=8^{(x+6)/3} is x=4

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32^{x-2}=8^{(x+6)/3}

3 2^{x - 2} = 8^{\frac{x + 6}{3}}

x = 4

Solution steps

3 2^{x - 2} = 8^{\frac{x + 6}{3}}

Apply exponent rules

5 (x - 2) = x + 6

Solve

5 (x - 2) = x + 6 : x = 4

x = 4

(3^{x})^{2} = 9^{x}

1 6^{x} = \frac{1}{2}

9^{x} = 3^{x + 1} + 4

ln (e^{8 x}) = 96

t, 40 = 12 0^{0.4 t} + 25

What is the answer to 32^{x-2}=8^{(x+6)/3} ?
The answer to 32^{x-2}=8^{(x+6)/3} is x=4
Solve for x: 32^{x-2}=8^{(x+6)/3}
The solution is x=4