What is the answer to (1/8)^{x+3}=16^{x-4} ?

The answer to (1/8)^{x+3}=16^{x-4} is x=1

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(1/8)^{x+3}=16^{x-4}

(\frac{1}{8})^{x + 3} = 1 6^{x - 4}

x = 1

Solution steps

(\frac{1}{8})^{x + 3} = 1 6^{x - 4}

Apply exponent rules

- 3 (x + 3) = 4 (x - 4)

Solve

- 3 (x + 3) = 4 (x - 4) : x = 1

x = 1

e^{\frac{2 x}{5}} = 25

e^{2 x} + 3 e^{x} = 18

6 e^{- 8 x} = 2

3^{p} = \frac{1}{9}

x, 4^{2 x} = 3

What is the answer to (1/8)^{x+3}=16^{x-4} ?
The answer to (1/8)^{x+3}=16^{x-4} is x=1
Solve for x: (1/8)^{x+3}=16^{x-4}
The solution is x=1