What is the answer to (sqrt(3))^x=27^{x-1} ?

The answer to (sqrt(3))^x=27^{x-1} is x= 6/5

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(sqrt(3))^x=27^{x-1}

(3)^{x} = 2 7^{x - 1}

x = \frac{6}{5}

Solution steps

(3)^{x} = 2 7^{x - 1}

Apply exponent rules

\frac{1}{2} x = 3 (x - 1)

Solve

\frac{1}{2} x = 3 (x - 1) : x = \frac{6}{5}

x = \frac{6}{5}

4^{3 x} = 1 6^{2 - x}

4^{x} = 2^{\frac{8}{x}}

5^{x} = \frac{2}{5}

x, x e^{y} + y e^{x} = 2

(\frac{1}{2})^{x} = 0.0625

What is the answer to (sqrt(3))^x=27^{x-1} ?
The answer to (sqrt(3))^x=27^{x-1} is x= 6/5
Solve for x: (sqrt(3))^x=27^{x-1}
The solution is x= 6/5