What is the answer to 2^{x+2}=8^{-x+8} ?

The answer to 2^{x+2}=8^{-x+8} is x= 11/2

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2^{x+2}=8^{-x+8}

2^{x + 2} = 8^{- x + 8}

x = \frac{11}{2}

Solution steps

2^{x + 2} = 8^{- x + 8}

Apply exponent rules

x + 2 = 3 (- x + 8)

Solve

x + 2 = 3 (- x + 8) : x = \frac{11}{2}

x = \frac{11}{2}

x, 5 (1.08)^{x} = 20

e^{4 - 4 x} = 6

lo g_{2} (x^{l o g_{2} (x)}) = 4

e^{2 x + 1} = 5

x, 4^{x} = 16 y

What is the answer to 2^{x+2}=8^{-x+8} ?
The answer to 2^{x+2}=8^{-x+8} is x= 11/2
Solve for x: 2^{x+2}=8^{-x+8}
The solution is x= 11/2