What is the answer to 6^{2+x}=8^{8+2x} ?

The answer to 6^{2+x}=8^{8+2x} is x=(ln(4194304/9))/(ln(3/32))

Solve for x: 6^{2+x}=8^{8+2x}

The solution is x=(ln(4194304/9))/(ln(3/32))

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6^{2 + x} = 8^{8 + 2 x}

x = \frac{ln ( \frac{4194304}{9} )}{ln ( \frac{3}{32} )}

Decimal Notation

x = - 5.51387 \dots

Solution steps

6^{2 + x} = 8^{8 + 2 x}

Apply exponent rules

(2 + x) ln (6) = (8 + 2 x) ln (8)

Solve

(2 + x) ln (6) = (8 + 2 x) ln (8) : x = \frac{ln ( \frac{4194304}{9} )}{ln ( \frac{3}{32} )}

x = \frac{ln ( \frac{4194304}{9} )}{ln ( \frac{3}{32} )}

e^{x - 7} = 8^{4 x}

1.0 2^{x} = 2

e^{- 2 x} = \frac{1}{3}

3^{2 x - 3} = 9

7^{2 x + 3} - 8 \cdot 7^{x + 1} + 1 = 0

What is the answer to 6^{2+x}=8^{8+2x} ?
The answer to 6^{2+x}=8^{8+2x} is x=(ln(4194304/9))/(ln(3/32))
Solve for x: 6^{2+x}=8^{8+2x}
The solution is x=(ln(4194304/9))/(ln(3/32))