What is the answer to 5^x=2^{x+1} ?

The answer to 5^x=2^{x+1} is x=(ln(2))/(ln(5)-ln(2))

Solve for x: 5^x=2^{x+1}

The solution is x=(ln(2))/(ln(5)-ln(2))

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5^{x} = 2^{x + 1}

x = \frac{ln ( 2 )}{ln ( 5 ) - ln ( 2 )}

Decimal Notation

x = 0.75647 \dots

Solution steps

5^{x} = 2^{x + 1}

Apply exponent rules

x ln (5) = (x + 1) ln (2)

Solve

x ln (5) = (x + 1) ln (2) : x = \frac{ln ( 2 )}{ln ( 5 ) - ln ( 2 )}

x = \frac{ln ( 2 )}{ln ( 5 ) - ln ( 2 )}

x^{5 + l o g_{10} (x)} = 1 0^{- 6}

3^{2 x + 3} = 243

x, 4^{x} + 5^{y} = 21

m, x^{m - 1} = 0

7^{x - 3} \cdot 98 = 14

What is the answer to 5^x=2^{x+1} ?
The answer to 5^x=2^{x+1} is x=(ln(2))/(ln(5)-ln(2))
Solve for x: 5^x=2^{x+1}
The solution is x=(ln(2))/(ln(5)-ln(2))