What are the solutions to the equation 4m^2-121=0 ?

The solutions to the equation 4m^2-121=0 are m= 11/2 ,m=-11/2

Find the zeros of 4m^2-121=0

The zeros of 4m^2-121=0 are m= 11/2 ,m=-11/2

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4 m^{2} - 121 = 0

m = \frac{11}{2}, m = - \frac{11}{2}

Solution steps

4 m^{2} - 121 = 0

Move

121

to the right side

4 m^{2} = 121

Divide both sides by

4

m^{2} = \frac{121}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = \frac{121}{4}, m = - \frac{121}{4}

\frac{121}{4} = \frac{11}{2}

- \frac{121}{4} = - \frac{11}{2}

m = \frac{11}{2}, m = - \frac{11}{2}

\frac{n}{9} < \frac{n}{2} - \frac{1}{3}

(\frac{2 i}{n})^{2}

\frac{1}{- i}

\frac{4}{35} + \frac{3}{10} - \frac{1}{12}

\frac{7 m}{( 5 m - 8 ) ( m - 4 )} + \frac{10}{( 3 m + 7 ) ( m - 4 )}

What are the solutions to the equation 4m^2-121=0 ?
The solutions to the equation 4m^2-121=0 are m= 11/2 ,m=-11/2
Find the zeros of 4m^2-121=0
The zeros of 4m^2-121=0 are m= 11/2 ,m=-11/2