What is the answer to 3^{x+1}(9^{2-x})= 1/3 ?

The answer to 3^{x+1}(9^{2-x})= 1/3 is x=6

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3^{x+1}(9^{2-x})= 1/3

3^{x + 1} (9^{2 - x}) = \frac{1}{3}

x = 6

Solution steps

3^{x + 1} (9^{2 - x}) = \frac{1}{3}

Apply exponent rules

x + 1 + 2 (2 - x) = - 1

Solve

x + 1 + 2 (2 - x) = - 1 : x = 6

x = 6

2^{x} - 3^{x} = 0

2^{2 x + 2} + 2^{x + 3} = 320

2^{x} + 2^{x + 3} = 72

e^{2 x} = 3^{x - 4}

3 \cdot 3^{x} = 2 7^{2 x}

What is the answer to 3^{x+1}(9^{2-x})= 1/3 ?
The answer to 3^{x+1}(9^{2-x})= 1/3 is x=6
Solve for x: 3^{x+1}(9^{2-x})= 1/3
The solution is x=6