What is the answer to 3(2^{x-3})=6^{x-1} ?

The answer to 3(2^{x-3})=6^{x-1} is x=-(ln(4/9))/(ln(3))

Solve for x: 3(2^{x-3})=6^{x-1}

The solution is x=-(ln(4/9))/(ln(3))

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3 (2^{x - 3}) = 6^{x - 1}

x = - \frac{ln ( \frac{4}{9} )}{ln ( 3 )}

Solution steps

3 (2^{x - 3}) = 6^{x - 1}

Apply exponent rules

ln (3) + (x - 3) ln (2) = (x - 1) ln (6)

Solve

ln (3) + (x - 3) ln (2) = (x - 1) ln (6) : x = - \frac{ln ( \frac{4}{9} )}{ln ( 3 )}

x = - \frac{ln ( \frac{4}{9} )}{ln ( 3 )}

9^{x - 10} = 1

5^{2 x + 1} - 24 (5^{x}) - 5 = 0

x, e^{2 x} = 4

e^{x^{2} - 3} = e^{2 x}

75 = 1 5^{x}

What is the answer to 3(2^{x-3})=6^{x-1} ?
The answer to 3(2^{x-3})=6^{x-1} is x=-(ln(4/9))/(ln(3))
Solve for x: 3(2^{x-3})=6^{x-1}
The solution is x=-(ln(4/9))/(ln(3))