What is the answer to (1/3)(3^{2x-1})=9 ?

The answer to (1/3)(3^{2x-1})=9 is x=2

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(1/3)(3^{2x-1})=9

(\frac{1}{3}) (3^{2 x - 1}) = 9

x = 2

Solution steps

(\frac{1}{3}) (3^{2 x - 1}) = 9

Multiply both sides by

3

3^{2 x - 1} = 27

Apply exponent rules

2 x - 1 = 3

Solve

2 x - 1 = 3 : x = 2

x = 2

e^{9 x} = 9 e^{x}

10 e^{- 2 x} = 2

2^{x} \cdot 4^{1 - x} = 5^{2 - x}

e^{3 x - 6} = 14

300 \cdot 5^{0.1 x} = 1000

What is the answer to (1/3)(3^{2x-1})=9 ?
The answer to (1/3)(3^{2x-1})=9 is x=2
Solve for x: (1/3)(3^{2x-1})=9
The solution is x=2